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⇤ ← Revision 1 as of 2004-03-31 17:43:42
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| n = LBS/SFS <= 8. | n = LBS:SFS <= 8:1. |
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| Suppose that LBS=8K and SFS=2K. Given a file of 18,000 bytes we would allocate {{{ 2 8K blocks + 1 2K block = 16384 + 2048 = 18,432 bytes. }}} |
Back to ComputerTerms
Terms:
- data blocks
- block sizes max ratio 8:1
- Allocation Example
- fragment recopying problem
- inodes
- direct blocks and indirect blocks, single, double and triple indirection
- directories, hard links and symbolic links
- mapping a file descriptor to an inode
See Also DiskStructures
Data Blocks
Data blocks contain whatever the user put into them. There are two sizes in Free BSD, one large block size (LBS) and smaller fragment size (SFS).
LBS = n x SFS LBS > SFS n = LBS:SFS <= 8:1.
Suppose that LBS=8K and SFS=2K. Given a file of 18,000 bytes we would allocate
2 8K blocks + 1 2K block = 16384 + 2048
= 18,432 bytes.Back to ComputerTerms